Final answer:
The relativistic kinetic energy of an object with a rest mass of 10018.7 MeV/c² moving with a ß of 0.129 is approximately 83.55 MeV.
Step-by-step explanation:
The question is asking to calculate the relativistic kinetic energy of an object with a rest mass of 10018.7 MeV/c² moving with a velocity represented by ß (beta) of 0.129.
To find the relativistic kinetic energy, we can use the formula K = (γ - 1)m0c², where γ (gamma) is the Lorentz factor, m0 is the rest mass, and c is the speed of light.
The Lorentz factor is given by γ = 1 / √(1 - ß²), with ß = v/c, where v is the object's velocity. For a ß of 0.129, γ can be calculated as approximately 1.0083.
Thus, the kinetic energy can be calculated as:
K = (1.0083 - 1) × 10018.7 MeV = 83.54891 MeV (approximately).
Therefore, the relativistic kinetic energy of the object is approximately 83.55 MeV.