Final answer:
The nitrite ion, NO−2, has a total of 19 valence electrons, which includes the extra electrons from its negative charge.
Step-by-step explanation:
To determine how many valence electrons the polyatomic ion nitrite, NO−2, has, we can follow these steps:
- Count the valence electrons of the nitrogen atom: N (5 valence electrons).
- Count the valence electrons of the oxygen atoms: O (6 valence electrons each) × 2 = 12 valence electrons.
- Add the electrons due to the negative charge: 2 extra electrons for the −2 charge.
- Sum the valence electrons: 5 (from N) + 12 (from both O's) + 2 (additional due to charge) = 19 valence electrons.
The nitrite ion has a total of 19 valence electrons. When depicting this as a Lewis structure, it is displayed in a set of brackets with the charge of the ion as a superscript outside of the brackets.