The equation of the line passing through the points (8, -3) and (4, 2) is y=− 5/2x+7.
To find the equation of the line passing through the points (8, -3) and (4, 2), we can use the slope-intercept form of a linear equation, which is y=mx+b, where m is the slope and b is the y-intercept.
First, calculate the slope (m) using the formula
m=
, where (x1,y1) and (x2,y2 ) are the coordinates of the two points.
m= 2−(−3)/4−8= 5/−4
Now that we have the slope, choose one of the points (let's use (8, -3)) to substitute into the equation. The slope-intercept form becomes
y=− 5/4x+b.
Substitute the coordinates of the point (8, -3) into the equation to solve for b:
−3=− 5/4×8+b
−3=−10+b
b=7
Now that we have the slope (−5/4) and the y-intercept (b=7), the equation of the line is y=− 5/4x+7. Therefore, the line passing through the points (8, -3) and (4, 2) can be represented by this equation.