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At 25°C, the formation of [Cu(NH3)4]2+ according to Equation 1 is most likely a:

The value of the formation constant of [Cu(NH3)4]2+ is 5.6 x 10^11 at 25°C.
A.Spontaneous process with positive ΔG°.
B.Spontaneous process with negative ΔG°.
C.Non-spontaneous process with positive ΔG°.
D.Non-spontaneous process with negative ΔG°."

User Cush
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1 Answer

1 vote

Final answer:

The formation of [Cu(NH3)4]2+ at 25°C is a spontaneous process with negative ΔG°.

Step-by-step explanation:

The formation constant (Kf) of [Cu(NH3)4]2+ is 5.6 x 10^11 at 25°C. A high value of formation constant indicates a stable complex ion. In this case, the complex ion is very stable. To determine if the formation of [Cu(NH3)4]2+ is spontaneous or non-spontaneous, we can look at the sign of the standard Gibbs free energy change (ΔG°). If ΔG° is negative, the process is spontaneous. However, if ΔG° is positive, the process is non-spontaneous.

Since the formation constant is large and positive, we can conclude that the formation of [Cu(NH3)4]2+ is a spontaneous process with negative ΔG°. This means that the complex ion is more stable than the individual ions and ammonia.

User John Ackerman
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