Question

What expression gives the amount of light energy (in J per photon) that is converted to other forms between the fluorescence excitation and emission events?

A. (6.62 × 10^(-34)) × (3.0 × 10^8)
B. (6.62 × 10^(-34)) × (3.0 × 10^8) × (360 × 10^(-9))
C. (6.62 × 10^(-34)) × (3.0 × 10^8) × [1 / (360 × 10^(-9)) - 1 / (440 × 10^(-9)]
D. (6.62 × 10^(-34)) × (3.0 × 10^8) / (440 × 10^(-9))

Answer 1

The correct expression for the light energy per photon converted to other forms between fluorescence excitation and emission events is option C, which considers the difference in energy between the higher energy excitation and lower energy emission wavelengths.

Step-by-step explanation:

The expression that gives the amount of light energy (in J per photon) that is converted to other forms between the fluorescence excitation and emission events is given by the energy difference of the photons associated with excitation and emission. The energy of a photon (E) can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 × 10-34 J·s), c is the speed of light (3.00 × 108 m/s), and λ is the wavelength of light in meters. For fluorescence, the excitation event involves a higher energy (shorter wavelength) and the emission event involves lower energy (longer wavelength).

Thus the energy converted to other forms is the difference in energy between these two events, which is option C: (6.62 × 10-34) × (3.0 × 108) × [1 / (360 × 10-9) - 1 / (440 × 10-9)].