Final answer:
The molar concentration of acetic acid in vinegar can be determined through a titration with sodium hydroxide, using the stoichiometric relationship from the reaction equation. The number of moles of NaOH used would equal the number of moles of acetic acid. By knowing the volume and concentration of NaOH, the concentration of acetic acid can be calculated using the volume of vinegar.
Step-by-step explanation:
To determine the molar concentration of acetic acid in vinegar through titration, we can use the provided stoichiometric equation C₂H₃O₂H + NaOH→ H₂O + CH₃CO₂Na. In this neutralization reaction, acetic acid reacts with sodium hydroxide in a 1:1 ratio. Therefore, the number of moles of NaOH used will be equal to the number of moles of acetic acid present in the vinegar. Using this relationship along with the volumes and concentrations of the reacting solutions would allow us to calculate the concentration.
Let's illustrate this with a hypothetical scenario (note that the actual volumes and concentrations of the reactants used in titration would need to be provided by the student for a precise calculation): If we titrated 25.0 mL of vinegar with a 0.100 M NaOH solution and we used 25.0 mL of NaOH to reach the endpoint, the moles of NaOH would be concentration times volume, which equates to 0.100 M * 0.025 L = 0.0025 moles. Since the mole ratio is 1:1, there would also be 0.0025 moles of acetic acid in the 25.0 mL of vinegar.
To find the concentration of acetic acid, divide the moles of acid by the volume of the vinegar in liters, giving us 0.0025 moles / 0.025 L = 0.100 M acetic acid.