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57th term of a arethmetic square that starts with -13 and subtracts 16

User Hardywang
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1 Answer

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Final answer:

The 57th term of the arithmetic sequence is -909.

Step-by-step explanation:

The given arithmetic sequence starts with -13 and subtracts 16. To find the 57th term, we can use the formula:

an = a1 + (n - 1)d

where an represents the nth term, a1 is the first term, n is the term number, and d is the common difference.

In this sequence, a1 = -13 and d = -16. Plugging these values into the formula, we get:

a57 = -13 + (57 - 1)(-16)

= -13 + 56(-16)

= -13 + (-896)

= -909

Therefore, the 57th term of the given arithmetic sequence is -909.

User Gambisk
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