Final answer:
The precipitation reaction between copper(II) chlorite and lithium sulfide correctly forms a precipitate of copper(II) sulfide and aqueous lithium chlorite. The correct reaction is Cu(ClO2)2 + Li2S --> CuS + 2 LiClO2.
Step-by-step explanation:
The correct listing of the precipitation reaction between aqueous solutions of copper(II) chlorite and lithium sulfide is Cu(ClO2)2 + Li2S → CuS + 2 LiClO2. In this reaction, copper(II) sulfide (CuS) is the precipitate that forms when these two reactants are combined.
According to solubility rules, most sulfide salts are insoluble, especially those of transition metals such as copper, leading to the formation of a solid precipitate. In solutions, reactants dissociate into their constituent ions before reacting to form the insoluble compound.