Final answer:
To find the largest possible value of AC + BC, we can use the Pythagorean theorem to find the lengths of AC and BC and then calculate their sum. The largest possible value of AC + BC can be written as a√2, where a is a positive integer and is not divisible by the square of any prime.
Step-by-step explanation:
To find the largest possible value of AC + BC, we need to analyze the given information.
From the information provided, we know that AB is a diameter of the circle, AC and BC are perpendicular to AB and intersect the chords PC and QC respectively.
Let's break down the problem step by step:
- First, we note that AP is equal to r, so PC is an altitude of the triangle APC.
- Since P is the midpoint of the semicircle, the measure of angle PAC is 90 degrees.
- This means that triangle APC is a right triangle with AC as the hypotenuse and PC as an altitude.
- Similarly, BQ is equal to r, so QC is an altitude of the triangle BQC.
- Again, the measure of angle QBC is 90 degrees, so triangle BQC is a right triangle with BC as the hypotenuse and QC as an altitude.
- We can use the Pythagorean theorem to find the lengths of AC and BC:
AC = √(AP^2 + PC^2) = √(r^2 + (2r)^2)
BC = √(BQ^2 + QC^2) = √(r^2 + (2r)^2)
Since AC and BC are equal, the largest possible value of AC + BC is 2 * AC = 2 * √(r^2 + (2r)^2).
Given that r is positive, the largest possible value of AC + BC can be written as a√(2) where a is a positive integer and is not divisible by the square of any prime.