Question

By titration, 15.0 ml of 0.1008 m sodium hydroxide is needed to neutralize a 0.1331 g sample of a weak awhat is the molar mass of the acid if it is monoprotic?express your answer in grams per mole to three significant figures.activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type. What is the molar mass of the monoprotic acid in grams per mole?

A) 36.3 g/mol
B) 43.2 g/mol
C) 64.8 g/mol
D) 72.6 g/mol

Answer 1

The molar mass of the monoprotic acid is 88.06 g/mol.

Step-by-step explanation:

To determine the molar mass of the monoprotic acid, we need to calculate the number of moles of the acid that reacted with the sodium hydroxide. From the titration, we know that 15.0 ml of 0.1008 M sodium hydroxide was needed to neutralize the acid. Using the equation for the reaction:

Acid + NaOH -> Salt + Water

We can construct a conversion factor:

0.1008 mol NaOH/1 L NaOH * 0.015 L NaOH = 0.001512 mol NaOH

Since the acid is monoprotic, 1 mol of the acid reacts with 1 mol of NaOH. Therefore, the molar mass of the acid is:

0.1331 g Acid / 0.001512 mol = 88.06 g/mol