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2068 (New+Old) Q.No. 1] In Victor-Meyer's apparatus 0.0623 g of volatile substance displace 31.5 mL of air at 23°C and 750 mm pressure. What is the molecular weight of the substance (Aqueous tension at 23°C = 21.1 mm)​

User Llazar
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Final answer:

To determine the molecular weight of a substance using Victor-Meyer's apparatus, we need to use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. By rearranging the equation and substituting the given values, we can calculate the moles and then divide the mass by the number of moles to find the molecular weight. The molecular weight is calculated as 52.27 g/mol.

Step-by-step explanation:

To calculate the molecular weight of the substance using Victor-Meyer's apparatus, we need to use the ideal gas law equation: PV = nRT. In this equation, P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. Rearranging the equation to solve for n, we get n = PV / RT.

First, let's convert the pressure to atm: 750 mmHg / 760 mmHg/atm = 0.9868 atm.

Next, convert the volume to liters: 31.5 mL / 1000 mL/L = 0.0315 L.

The temperature is given as 23°C, so we need to convert it to Kelvin: 23°C + 273.15 = 296.15 K.

Now we can calculate the number of moles (n) using the equation n = PV / RT: n

= (0.9868 atm)(0.0315 L) / (0.08206 L.atm/K.mol)(296.15 K)

= 0.00119 mol.

To find the molecular weight of the substance, we need to divide the mass of the substance by the number of moles.

Molecular weight = mass of substance / number of moles

= 0.0623 g / 0.00119 mol

= 52.27 g/mol.

User Dimitrius Lachi
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