Final answer:
The energy input in joules necessary to remove 48,000 British thermal units (BTUs) from a cold environment in 1.00 hour with an energy efficiency rating (EER) of 12.0 is approximately 169,504 J.
Step-by-step explanation:
The energy input in joules necessary to remove 48,000 British thermal units (BTUs) from a cold environment in 1.00 hour can be calculated using the energy efficiency rating (EER) of the air conditioner. The EER is defined as the number of BTUs of heat transfer from a cold environment per hour divided by the watts of power input. In this case, the EER is 12.0, so the energy input can be calculated as:
Energy input in joules = EER * BTUs / 3.41
Energy input in joules = 12.0 * 48,000 / 3.41 = 169,504 J
Therefore, the energy input in joules necessary to remove 48,000 BTUs from a cold environment in 1.00 hour with an EER of 12.0 is approximately 169,504 J.