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If the specific heat of glass is .196, how many btu are needed to raise the temperature of 10 pounds of glass from 50° F to 70°F?

A) 40.2
B) 39.2
C) 59.2
D) 36.2

User NVRAM
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1 Answer

1 vote

Final answer:

The heat transfer required to raise the temperature of 10 pounds of glass from 50°F to 70°F is approximately 89.0232 BTU.

Step-by-step explanation:

To calculate the heat transfer required to raise the temperature of 10 pounds of glass from 50°F to 70°F, we can use the formula: Q = mcΔT, where Q is the heat transfer, m is the mass of the glass, c is the specific heat of glass, and ΔT is the change in temperature. First, we need to convert 10 pounds to kilograms by multiplying it by 0.4536. Then, we can calculate the heat transfer using the formula.

Q = (10 × 0.4536) × 0.196 × (70 - 50)

Q = 4.536 × 0.196 × 20

Q = 89.0232 BTU

Therefore, approximately 89.0232 BTU are needed to raise the temperature of 10 pounds of glass from 50°F to 70°F.