Question

Solve each question. (Hint: Factor using zero product property)

(3x+2)(x-5)=0

x^2 + 12x + 32=0

x^2 - 11x - 39 = 3

x^2 - 9x + 10 = -8

25x^2+19x+4=0

7x^2-33x=10=0

Answer 1

To solve the equation (3x+2)(x-5)=0, set each factor equal to zero and solve for x. The solutions are x = -2/3 and x = 5.

Step-by-step explanation:

To solve the equation (3x+2)(x-5)=0 using the zero product property, we set each factor equal to zero and solve for x.

1. Setting 3x+2 = 0, we get x = -2/3.
2. Setting x-5 = 0, we get x = 5.

Therefore, the solutions to the equation are x = -2/3 and x = 5.