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According to the following reaction: 2Cu(s) + O₂(g) ----> + 2CuO(s) If the percentage yield is 96.7% how many grams of CuO will be produced from 13.4 g of Cu?

A) 12.97 g
B) 25.95 g
C) 50.00 g
D) 100.00 g

User Rob Darwin
by
7.5k points

1 Answer

5 votes

Final answer:

A) 12.97 g.The actual yield of CuO produced from 13.4 g of Cu with a percentage yield of 96.7% is calculated to be 16.20 g. However,

Step-by-step explanation:

To find out how many grams of CuO will be produced from 13.4 g of Cu with a percentage yield of 96.7%, we first need to calculate the theoretical yield of CuO. The molar mass of Cu (copper) is 63.55 g/mol, and the molar mass of CuO is 79.55 g/mol. Using stoichiometry, we can determine that 1 mol of Cu will produce 1 mol of CuO.

Therefore, 13.4 g of Cu is equivalent to 13.4 g / 63.55 g/mol = 0.2108 mol of Cu, which should produce the same amount in moles of CuO:

0.2108 mol of CuO × 79.55 g/mol = 16.76 g of CuO

This is the theoretical yield. Now we apply the percentage yield:

Percentage yield = Actual yield / Theoretical yield × 100%

Hence, the actual yield = Percentage yield × Theoretical yield / 100% = 96.7% × 16.76 g / 100% = 16.20 g of CuO.

Therefore, the closest answer to the options provided is (A) 12.97 g, but this is abecause with the percentage yield, the actual calculated yield should be 16.20 g which is not one of the provided answer choices. Please check the question and the answer choices for any possible errors.

User ElectroBit
by
9.0k points
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