Final answer:
It is true that we do not pass addresses to the print f function to print the value of a char variable; instead, we pass the char variable itself.
Step-by-step explanation:
C++ printf is a formatting function that is used to print a string to stdout. The basic idea to call printf in C++ is to provide a string of characters that need to be printed as it is in the program. The print f in C++ also contains a format specifier that is replaced by the actual value during execution. The printf command converts, formats, and writes its Argument parameters to standard output.
The Argument parameters are formatted under control of the Format parameter. The formatted output line cannot exceed LINE_MAX bytes in length. The statement "We do not pass addresses to printf, in order to print the value of a char variable(e.g. %c)" is True. When using printf in the C programming language to print a character, you pass the actual character variable, not its address.
For example, if char c = 'A'; is your character variable, you would write printf("%c", c); to print the letter 'A'. Passing the address of the variable would actually require using the '%p' format specifier to print the memory address, or '%s' if you were dealing with a string (which is essentially a character array).