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Consider int ia[2], *ip; ip = &ia; ia[0] = 1; ia[1]=2; *(ip + 1) = *ip+1; What is the value of ia[0]?

1 Answer

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Final answer:

The value of ia[0] is 1.

Step-by-step explanation:

The value of ia[0] can be determined by examining the given code snippet. The snippet declares an array ia of size 2 and a pointer variable ip. The pointer ip is assigned the address of the first element of ia. The elements of ia are then initialized with the values 1 and 2. The expression *(ip + 1) dereferences the pointer ip and adds 1 to its index. This value is then assigned to the second element of ia. Therefore, the value of ia[0] remains unchanged and is still equal to 1.

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