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How many grams of calcium phosphate can be produced from the reaction of 2.50 L of 0.250 M Calcium chloride with an excess of phosphoric acid?

A) 31.25 g
B) 62.50 g
C) 125.00 g
D) 250.00 g

User Luqi
by
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1 Answer

3 votes

Final answer:

To calculate the grams of calcium phosphate produced, we must use stoichiometry and the given information from the reaction. The correct answer is 64.37 g.

Step-by-step explanation:

To determine the number of grams of calcium phosphate that can be produced, we need to use the stoichiometry of the balanced chemical equation and the given information. The balanced equation for the reaction between calcium chloride and phosphoric acid is:

3 CaCl₂ + 2 H₃PO₄ → Ca₃(PO₄)₂ + 6 HCl

From the equation, we can see that the ratio between moles of calcium chloride and moles of calcium phosphate is 3:1. First, calculate the number of moles of calcium chloride:

2.50 L × 0.250 M = 0.625 mol

Since the ratio is 3:1, 0.625 mol of calcium chloride will produce 0.625/3 = 0.208 mol of calcium phosphate. Finally, calculate the mass of calcium phosphate:

Mass = moles × molar mass = 0.208 mol × 310.18 g/mol = 64.37 g

Therefore, the correct answer is D) 64.37 g.

User Jonah
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