Question

What is output when the following code is executed?

int x = 1;
while (x <= 5) {
cout << "Repeat " ;
}
cout << "Done!" << endl;

Answer 1

The code provided creates an infinite loop that repeatedly prints the string 'Repeat'.

Step-by-step explanation:

The code provided creates an infinite loop. The variable x is initialized to 1. The while loop condition (x <= 5) is always true, so the loop continues indefinitely.

Each time the loop runs, it prints the string 'Repeat ' to the console. However, since there is no code inside the loop that modifies the value of x, it remains at 1 and the condition remains true indefinitely, resulting in an infinite number of repetitions of the word 'Repeat' on the console.

The code outside the loop prints 'Done!' followed by a new line ('endl') after the loop completes. However, since the loop is infinite, this code is never reached and 'Done!' is never printed.

When the given code is executed, it results in an infinite loop. The variable x is initialized to 1, and the condition of the while loop checks if x is less than or equal to 5. However, there is no increment or modification to the value of x within the while loop.

Consequently, the condition always evaluates to true, causing the cout statement to repeatedly print 'Repeat ' without end. The text 'Done!' will never be printed because the loop does not have a break condition and the program will never reach the statement after the while loop.