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What will be output when the following code is executed?

for (int x=1; x <= 5; x++) {
cout << "One ";
}
cout << "Done!" << endl;

User Gee
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1 Answer

4 votes

Final answer:

The code will output 'One One One One One Done!' with 'One ' printed five times, followed by 'Done!' on a new line.

Step-by-step explanation:

When the given code is executed, the output will be:

One One One One One Done!

This is because the for loop in the code will run five times, as it starts with int x=1 and continues until x <= 5, incrementing x by 1 after each iteration. During each iteration, the statement cout << "One "; is executed, which prints 'One ' to the console.

After exiting the loop, the final statement cout << "Done!" << endl; is executed, which prints 'Done!' followed by a new line. Thus, the word 'One ' is printed five times followed by 'Done!' on a new line.

User Chrissy
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