Question

What is output when the following code is executed?

int x = 7;
while (x <= 5) {
cout << "Repeat " ;
x = x + 1;
}
cout << "Done!" << endl;

Answer 1

The code outputs "Done!" because the condition for the while loop is not met, and hence, the loop is not executed.

Step-by-step explanation:

When the code int x = 7; while (x <= 5) { cout << "Repeat " ; x = x + 1;}cout << "Done!" << endl; is executed, it will output "Done!". This is because the condition in the while loop, x <= 5, is not satisfied since x starts at 7. Therefore, the loop is never entered, and the program goes directly to print "Done!".

Here's what happens:

int x = 7; initializes the variable x with the value 7.

The while loop checks the condition x <= 5, which is initially true (7 is not less than or equal to 5). Therefore, the code inside the loop will not execute because the condition is already false.

As a result, the loop body, which contains cout << "Repeat "; and x = x + 1;, won't be executed even once.

The program will move outside the loop and directly execute cout << "Done!" << endl;.

So, when you execute this code, the output will be simply: