69.6k views
4 votes
What does the following code do when executed?

for (int i=1; i<=10; i++) {
for (int j=1; j<=4; j++) {
cout << "*";
cout << endl;
}
}

User SubZero
by
8.2k points

1 Answer

4 votes

Final answer:

The given C++ code uses nested for loops to print a pattern in which it outputs ten lines, each with four asterisks, forming a rectangle shape on the screen.

Step-by-step explanation:

The code in question uses nested for loops and is a common programming construct used in Computer Science. It is written in C++ and when executed, it prints a pattern of asterisks (*). Specifically, the outer loop runs ten times, indicated by int i=1; i<=10; i++, and for each iteration of the outer loop, the inner loop runs four times, indicated by int j=1; j<=4; j++.

During each inner loop iteration, one asterisk is printed followed by a newline character, due to the cout statements. As a result, the program outputs ten lines, each containing four asterisks, thereby forming a rectangle of asterisks on the screen.

User Ruben Trancoso
by
8.0k points