Question

A 220.9g sample of an unknown object is heated using 130.2 J such that its temperature rises 2.8°C. What is the specific heat of this unknown object? Report your answer to the hundredths spot #.##

Answer 1

The specific heat of the unknown object is calculated using the formula Q = mcΔT and is found to be 0.2105 J/g°C based on the given data of heat transfer, mass, and temperature change.

Step-by-step explanation:

To calculate the specific heat of the unknown object, we can use the formula for heat transfer given by Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

We are provided with the heat transferred (Q = 130.2 J), the mass (m = 220.9 g), and the temperature change (ΔT = 2.8°C).

Solving the formula for specific heat capacity c, we get:

c = Q / (mΔT)

c = 130.2 J / (220.9 g × 2.8°C)

c = 130.2 J / (618.52 g°C)

c = 0.2105 J/g°C

Therefore, the specific heat of the unknown object is 0.2105 J/g°C