144k views
2 votes
"Which of the following expression could be accepted in Java?

a. Func extract = delegate (int p) { p.getAge(); }
b. Predicate allDrivers = p => p.getAge() >= 16;
c. Predicate allDrivers = p -> p.getAge() >= 16;
d. All of the above.

User Kounavi
by
8.5k points

1 Answer

5 votes

Final answer:

The valid Java expression is 'c. Predicate allDrivers = p -> p.getAge() >= 16;', which defines a lambda expression checking if a driver's age is 16 or over using Java's lambda syntax.

Step-by-step explanation:

The correct expression that could be accepted in Java is option c. Predicate allDrivers = p -> p.getAge() >= 16. This is a lambda expression introduced in Java 8. The lambda operator '->' is used to define the body of the lambda expression, and the expression p.getAge() >= 16 returns a boolean value based on the age of the driver.

The correct expression that could be accepted in Java among the options provided is c. Predicate allDrivers = p -> p.getAge() >= 16; This is the syntax used in Java to declare a Predicate, which is a functional interface that represents a condition (or predicate) that evaluates to true or false. This specific lambda expression checks if the age of a driver retrieved by the get Age() method is greater than or equal to 16.

TheOptionsand b use syntax that is not recognized in Java. Option a resembles delegate usage in C# and option b uses the '=>' lambda expression syntax, which is also not part of Java's syntax. In Java, lambda expressions use the '->' syntax.

User Alsotang
by
7.3k points