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Some people say that more babies are born in September than in any other month. To test this claim, you take a random sample of 150 students at your school and find that 21 of them were born in September.

You are interested in whether the proportion born in September is greater than 1/12—what you would expect if September was no different from any other month.
Thus your null hypothesis is He: p=1/12. The P-value for your test is 0.0056. Which of the following statements correctly interprets the P-value?
(a) The probability that September birthdays are no more common than any other month is 0.0056.
(b) The probability that September birthdays are more common than other months is 0.0056.
(c) The probability that the proportion of September birthdays is not equal to 1/12 is 0.0056.
(d) Assuming that the proportion of babies born in September is the same as any other month,
there is a 0.0056 probability of getting a sample proportion of 21/150 or greater by chance alone.
(e) Assuming that the proportion of babies born in September is greater than any other month,
there is a 0.0056 probability of getting a sample proportion of 21/150 or greater by chance alone.

User GoldenJam
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Final answer:

The correct interpretation of the P-value is (d) Assuming that the proportion of babies born in September is the same as any other month, there is a 0.0056 probability of getting a sample proportion of 21/150 or greater by chance alone.

Step-by-step explanation:

The correct interpretation of the P-value is (d) Assuming that the proportion of babies born in September is the same as any other month, there is a 0.0056 probability of getting a sample proportion of 21/150 or greater by chance alone.

User Mark Travis
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