187,730 views
23 votes
23 votes
How many moles of CaCl₂ would there be in 42 mL of 2.09 M aqueous CaCl₂ solution?

3 significant figures

User Pavlo Glazkov
by
2.4k points

1 Answer

22 votes
22 votes

Answer:

0.0878 moles CaCl₂

Step-by-step explanation:

To find the amount of moles of CaCl₂, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the amount of moles (M = moles / L)

It is important to arrange the conversions in a way that allows for the cancellation of units.

(Step 1)

42 mL CaCl₂ 1 L
------------------------ x ---------------------- = 0.042 L CaCl₂
1,000 mL

(Step 2)

Molarity (M) = moles / volume (L) <----- Molarity ratio

2.09 M = moles / 0.042 L <----- Insert values

0.0878 = moles <----- Multiply both sides by 0.042 L

User Fandro
by
3.2k points