Main Answer:
1. BrF3
2. PI3
3. SeBr2
4. NOBr
Therefore, the correct answer is all of these.
Step-by-step explanation:
BrF3 is bent due to the lone pair on the central atom, resulting in a trigonal bipyramidal molecular geometry. PI3 is tetrahedral as it has three bonding pairs and one lone pair around the central phosphorus atom. SeBr2 is nonpolar as it has a linear molecular geometry, with the two bromine atoms symmetrically placed around the selenium atom, canceling out the dipole moments.
NOBr has a bond angle of 180 degrees due to its linear molecular geometry, where the nitrogen is bonded to the oxygen and bromine atoms. In summary, the molecular shapes and characteristics of these compounds are determined by the arrangement of atoms and lone pairs around the central atom.
Therefore, the correct answer is all of these.