Final answer:
HCN is the only linear molecule with no lone pairs and sp hybridization. NOBr, NO-, and NBr3 are molecules that have atoms with nonzero formal charges, with NBr3 having sp3 hybridization.
Step-by-step explanation:
When drawing Lewis structures for NOBr, NO-, HCN, and NBr3, consider the total number of valence electrons for each molecule to ensure that each atom achieves a full octet where possible, or in the case of boron and hydrogen, a satisfied valence shell. Here is a breakdown responding to the student's query:
- HCN is a linear molecule with no lone pairs on either the hydrogen or nitrogen. Nitrogen is sp hybridized in HCN, forming a triple bond with carbon and a single bond with hydrogen.
- NOBr is a nonlinear molecule and has lone pairs on both the nitrogen and bromine atoms. Nitrogen has one lone pair, and bromine has three. This molecule displays a range of formal charges, due to the bonding arrangement.
- The anion NO- has one lone pair on the nitrogen atom and is bent due to the lone pair-bonding pair repulsion. Nitrogen here has a nonzero formal charge.
- NBr3 is a trigonal pyramidal molecule with sp3 hybridization and a lone pair on the nitrogen atom. Here, nitrogen will have a nonzero formal charge.
To quickly summarize:
- The only linear molecule is HCN.
- The molecule with no lone pairs is HCN.
- The molecule with sp3 hybridization is NBr3.
- Molecules with an atom with nonzero formal charge are NOBr, NO-, and NBr3.