Question

Draw lewis structures for SiS2, IBr3, TeBr2, KrBr2

1. which of the molecules are bent
2. which of the molecules are trigonal bipyramidal
3. which of the molecules are nonpolar
4. which of the molecules contain 180 bond angles

Answer 1

To draw the Lewis structures for SiS2, IBr3, TeBr2, and KrBr21, we need to consider the number of valence electrons in each atom and their bonding patterns. SiS2 and TeBr2 are bent molecules and nonpolar, while IBr3 and KrBr21 are trigonal bipyramidal and polar. None of the molecules have 180 bond angles.

Step-by-step explanation:

Let's draw the Lewis structures for the given molecules:

1. SiS2: The Lewis structure for SiS2 will have two sulfur atoms bonded with a silicon atom and two lone pairs of electrons on each sulfur atom. The molecule is bent.
2. IBr3: The Lewis structure for IBr3 will have three bromine atoms bonded with an iodine atom. The molecule is trigonal bipyramidal.
3. TeBr2: The Lewis structure for TeBr2 will have two bromine atoms bonded with a tellurium atom. The molecule is bent.
4. KrBr21: The Lewis structure for KrBr21 will have one bromine atom bonded with a krypton atom and two lone pairs of electrons on the bromine atom. The molecule is bent.

To determine which of the molecules are nonpolar, we need to check if they have a symmetrical shape. In this case, SiS2 and TeBr2 are nonpolar because they have a symmetrical bent shape. IBr3 and KrBr21 are polar.

None of the molecules have 180 bond angles, as their bond angles depend on their molecular structures.