Question

Consider the following code: REPEAT UNTIL (x mod 2 = 1) x ← x + 3. Assume that x is initially 6. How many times will the loop iterate?

Answer 1

The given code will iterate once.

Step-by-step explanation:

The given code is a REPEAT UNTIL loop that iterates until the condition (x mod 2 = 1) is true. The loop updates the value of x by adding 3 in each iteration.

In this case, x is initially 6. Let's determine how many times the loop will iterate.

Step 1: Check if the condition (x mod 2 = 1) is satisfied:

• 6 mod 2 = 0, so the condition is not satisfied.

Step 2: Update the value of x by adding 3: x = 6 + 3 = 9.

Step 3: Repeat steps 1 and 2:

• 9 mod 2 = 1, so the condition is satisfied.

The loop will iterate once because the condition is only satisfied after updating x once.