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The algorithm below is used to simulate the results of rolling a standard 6-sided die 5 times. Consider the goal of determining whether the simulation resulted in more results which were odd than results which were even.

Step 1: Initialize the variables odd_counter and roll_counter to 0.
Step 2: A variable dice_roll is randomly assigned an integer value between 1 and 6 inclusive. If dice_roll has a value of 1, 3 or 5, then odd_counter is incremented by 1.
Step 3: Increment the value of roll_counter by 1.
Step 4: Repeat steps 2 and 3 until roll_counter equals 5.
Following the execution of the algorithm, which of the following expressions indicates that the simulation resulted in more results which were odd than results which were even?
1) odd_counter > roll_counter/2
2) odd_counter ≥ roll_counter/2
3) odd_counter < roll_counter/2
4) odd_counter ≤ roll_counter/2

1 Answer

4 votes

Final answer:

The correct expression is odd_counter > roll_counter/2, as it indicates that there were more odd results.

Step-by-step explanation:

The goal is to determine whether the simulation resulted in more results which were odd than results which were even. In the algorithm, the variable odd_counter is incremented by 1 if the dice_roll is 1, 3, or 5. The variable roll_counter is incremented by 1 with each roll.

To determine if the simulation resulted in more odd results than even results, we can compare the value of odd_counter and roll_counter/2.

The correct expression is odd_counter > roll_counter/2, as it indicates that there were more odd results.

User Pavel Uspenskiy
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