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In a triple cross of a triple heterozygous (st+.ss+.e+/ .e) Drospholia female with a triple homozygous male ( .e/ .e), 755 progeny were produced with the following genotypes: 561 - st+.ss+.e+/ .e and .e/ .e = 74.3, 102 - st+.ss.e/ .e and +.e+/ .e = 13.5, 84 - st+.ss+.e/ .e and .e+/ .e = 11.1, 8 - st+.ss.e+/ .e and +.e/ .e = 1.1. What is the relative distance between these three genes?

User Toojays
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Final answer:

The relative distances between three genes are inferred from the percentages of recombinant offspring compared to parental types.

Step-by-step explanation:

To determine the relative distance between three genes in Drosophila, we need to examine the progeny from a genetic cross.

The progeny in this question shows different combinations of phenotypes which are a result of genetic recombination. The relative distances between genes can be inferred by the percentage of recombinant offspring.

Recombinant offspring are less frequent than the parental type because they result from crossing over during meiosis.

In this scenario, the given percentages 74.3%, 13.5%, 11.1%, and 1.1% represent the offspring frequencies for different genotypic combinations.

Since the highest percentage (74.3%) represents the parental genotypes, we can assume that the genotypes with lower percentages are the result of recombination.

To accurately calculate the map distances, we would sum up the percentages of the recombinant offspring and divide by the total number of offspring to get the recombination frequency for each gene pair.

However, the specific genotypes provided are not sufficient to calculate the exact recombination frequencies for each gene pair or to determine the order of genes.

Additional information about the parental genotypes and a clear distinction between the recombinant and non-recombinant progeny would be required to perform this analysis in a real-world scenario.

User WiredIn
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