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3. A beach ball is inflated to a volume of 25L of air at 15°C. During the afternoon, the volume increases by 1L. What is the new temperature outside?
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3. A beach ball is inflated to a volume of 25L of air at 15°C. During the afternoon,

the volume increases by 1L. What is the new temperature outside?

3. A beach ball is inflated to a volume of 25L of air at 15°C. During the afternoon-example-1
User Granty
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1 Answer

11 votes
11 votes

Answer:

Below

Step-by-step explanation:

P1V1/T1 = P2V2/T2 T MUST be in Kelvin

P1 = P2 so this becomes

V1/T1 = V2/T2

25/ (273.15 + 15) = 26 / (273.15 + X) where 'X' is the °C afternoon temp

X = 26.5 °C

User Jason Crease
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2.8k points
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