Final answer:
The statement is false; if the opponent always wins the pumping lemma game, it indicates that L is not regular because it fails to meet the conditions set by the pumping lemma for regular languages.
Step-by-step explanation:
If the opponent can always win in the pumping lemma game, regardless of what moves you make, then L is not regular. This statement is false. The pumping lemma for regular languages is a property that describes how words in a regular language can be 'pumped' (i.e., have some middle part repeated many times) and still belong to the same language. If the opponent, representing the language in question, can always win, this means that for any division of the string into three parts (x, y, z) satisfying the pumping lemma's conditions, the string xynz (for any n) is not in the language. This is, in fact, a proof that the language is not regular, since it violates the conditions of the pumping lemma for regular languages.