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A ball dropped and accelerates downwards at a rate of 10m/s^2 for 15 seconds how much will the balls velocity increase

1 Answer

7 votes

Answer:

v = 150 m/s

Step-by-step explanation:

Given that,

The acceleration of the ball, a = 10 m/s²

Time, t = 15 s

We need to find the increase in ball's velocity. When it is dropped its initial velocity is equal to 0. Let v be the velocity,

v = u+at

v = 0 +10(15)

v = 150 m/s

So, the ball's final velocity is 150 m/s.

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