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How much current does a 10 kΩ resistor draw from a 12.0 V battery?

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Final answer:

To calculate the current through a resistor, we use Ohm's Law. By rearranging the equation V = IR to solve for I, we can find the current through the resistor. In this case, a 10 kΩ resistor draws approximately 0.0012 A of current from a 12.0 V battery.

Step-by-step explanation:

To calculate the amount of current a resistor draws from a battery, we use Ohm's Law, which states that V = IR, where V is the voltage, I is the current, and R is the resistance.

In this case, the voltage of the battery is 12.0 V and the resistance of the resistor is 10 kΩ (or 10,000 Ω).

Using Ohm's Law, we can rearrange the equation to solve for the current:

I = V / R

Plugging in the values, we get:

I = 12.0 V / 10,000 Ω

I ≈ 0.0012 A

Therefore, the 10 kΩ resistor draws approximately 0.0012 Amperes of current from the 12.0 V battery.

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