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Kirchoff's Voltage Law for a series circuit shows that the total voltage dropped in a series circuit is equal to the _______ of the individual voltage drops.

User Bludzee
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Final answer:

Kirchhoff's Voltage Law states that in a series circuit, the total voltage supplied by the source is equal to the sum of the individual voltage drops across each resistor.

Step-by-step explanation:

Kirchhoff's Voltage Law for a series circuit shows that the total voltage dropped in a series circuit is equal to the sum of the individual voltage drops. This is often known as Kirchhoff's loop law which states that the algebraic sum of potential differences (voltages) in any closed circuit loop must be zero. Applying this to a series circuit, where each resistor has the same current flowing through it due to the single pathway for charge flow, we can use Ohm's law, V = IR, to determine the voltage drop across each resistor.

The total voltage supplied by the voltage source is thus equal to the sum of the voltage drops across all resistors in the loop. If we have resistors R₁, R₂, and R₃ connected in series with a voltage source, the voltage drops V₁, V₂, and V₃ across each resistor would be V₁ = IR₁, V₂ = IR₂, and V₃ = IR₃ respectively. Therefore, Kirchhoff's Law can be expressed as V source = V₁ + V₂ + V₃, which means the electromotive force (emf) equals the sum of the IR (voltage) drops.

User Soumia
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