165k views
2 votes
A patient's C(a-v)O2 has increased from 4.2 to 7.4 vol% following an increase in PEEP from 10 to 15 cm H2O. Which of the following best explains these data?

A. reduced cardiac output
B. decreased ventilation
C. alveolar overdistension
D. increase cardiac index

User Aimee
by
7.0k points

1 Answer

4 votes

Final answer:

The increased C(a-v)O2 from 4.2 to 7.4 vol% after an increase in PEEP suggests reduced cardiac output, as PEEP can affect hemodynamics by decreasing venous return and cardiac output.

Step-by-step explanation:

A patient's C(a-v)O2 has increased from 4.2 to 7.4 vol% after PEEP was raised from 10 to 15 cm H2O. This change suggests that there is a greater extraction of oxygen by the tissues because of a higher differential between arterial and venous oxygen, which is often indicative of reduced cardiac output. Essentially, as the tissues extract more oxygen due to reduced blood flow, the C(a-v)O2 widens. Altered PEEP can affect lung mechanics and hemodynamics, often causing a decrease in cardiac output due to an increase in intrathoracic pressure, which reduces venous return and subsequently cardiac output.

Decreased ventilation generally would not cause an increase in C(a-v)O2, as it would likely lead to both reduced arterial and venous oxygen saturation. Alveolar overdistension typically refers to lung injury due to high PEEP, not directly influencing C(a-v)O2. An increased cardiac index signifies improved cardiac output, which would typically lead to a narrower C(a-v)O2, contrary to the scenario described.

User Johannes Gorset
by
7.7k points