Final answer:
The physics question about determining the height of an object after it's dropped involves using kinematic equations that relate distance fallen to time in freefall. The formula s(t) = 16t^2 represents the distance fallen by an object in freefall on Earth in the Imperial system. To find the height at a specific time, the correct formula including the initial height and gravity is needed.
Step-by-step explanation:
The question regarding the height of an object after being dropped from a certain altitude pertains to the domain of Physics, more specifically, kinematics, which is the study of motion. To determine the height of a rock after it has been dropped from a bridge, we need to utilize the formula that relates distance fallen to time in freefall, considering the acceleration due to gravity.
In this case, the provided formula is s(t) = 16t^2 which applies to objects in freefall near the Earth's surface (using the Imperial system where acceleration due to gravity ≈ 32 feet per sec2). However, this formula doesn't seem to correlate with the given height of the bridge (906 feet, assuming this refers to the initial height). Typically, the formula h = h0 - (1/2)gt^2 where h is the final height, h0 is the initial height, g is the acceleration due to gravity (32 feet per second squared), and t is the time elapsed would be used.
Using this correct formula, we would solve for the time it takes for the rock to hit the ground and then use that time to find the height at any given moment while the rock is in freefall. Unfortunately, no specific time (t) after the drop is provided in the question to find the height at that particular moment.