Question

According to the label, a vial containing one gram Ceftotaxime should be reconstituted with 3 mL sterile water. The dosage strength will be 300 mg/mL. Round answer to the nearest tenth of a mL. Calculate how many mL will be in the one gram vial after reconstitution?

Answer 1

After reconstitution of one gram of Ceftotaxime with 3 mL sterile water, the vial will contain approximately 3.3 mL of solution at a concentration of 300 mg/mL.

Step-by-step explanation:

The question asks how many milliliters will be in a one gram vial after reconstitution when a gram of Ceftotaxime is reconstituted with 3 mL of sterile water to achieve a dosage strength of 300 mg/mL. To solve for this, we need to use the concentration formula which relates mass (m), volume (V), and concentration (c). The formula is c = m/V, which we can rearrange to find the volume as V = m/c. Given that the mass (m) is 1 gram (1,000 mg) and the concentration (c) is 300 mg/mL, we can calculate the volume (V) after reconstitution.

Using the formula, V = m/c, we substitute the given values to get V = 1,000 mg / 300 mg/mL. This gives us a volume of approximately 3.3 mL after reconstitution (rounding to the nearest tenth). It's important to note that we must consider both the volume of powder and the solvent to determine the final volume of the solution. However, since the initial volume is given by the vial label, we only need to focus on the solution after reconstitution.