Final answer:
The pixel size for a 2,048 × 2,048 matrix with a 60-cm FOV is approximately 0.293 mm, obtained by dividing the field of view in mm by the number of pixels.
Step-by-step explanation:
To calculate the pixel size of a 2,048 × 2,048 matrix with a 60-cm field of view (FOV), you need to divide the FOV by the number of pixels in one dimension. Here's the formula to calculate pixel size: Pixel Size = FOV / Matrix Size. In this case, it would be Pixel Size = 60 cm / 2048 pixels. First, convert 60 cm to mm by multiplying by 10 (since 1 cm = 10 mm), which gives us 600 mm. Then, divide 600 mm by 2048 pixels to get the pixel size in mm.
Pixel size = 600 mm / 2048 pixels ≈ 0.293 mm (rounded to three decimal places). So, the pixel size for a 2,048 × 2,048 matrix with a 60-cm FOV is approximately 0.293 mm.
The pixel size of a 2,048 × 2,048 matrix with a 60-cm field of view (FOV) can be calculated by dividing the FOV by the number of pixels in each dimension. In this case, the FOV is 60 cm and the matrix has 2,048 pixels in each dimension. So, the pixel size would be:
Pixel size = FOV / Number of pixels
Pixel size = 60 cm / 2048 pixels
Pixel size ≈ 0.030 cm or 0.3 mm