212k views
2 votes
Exposure factors of 110 kVp and 12 mAs are used with an 8:1 grid for a particular exposure. What should be the new mAs if a 12:1 grid is substituted?

15

User Battmanz
by
8.4k points

1 Answer

1 vote

Final answer:

To calculate the new mAs when a 12:1 grid is substituted, use the formula: mAs(new) = mAs(old) x (grid factor(new) / grid factor(old)). Substituting the values, the new mAs should be approximately 11.2 mAs.

Step-by-step explanation:

To calculate the new mAs when a 12:1 grid is substituted, we can use the formula:

mAs(new) = mAs(old) × (grid factor(new) / grid factor(old))

First, let's calculate the grid factors:

Grid factor(old) = (1 / grid ratio(old)) + 1 = (1 / 8) + 1 = 1.125

Grid factor(new) = (1 / grid ratio(new)) + 1 = (1 / 12) + 1 = 1.083

Now, we can substitute the values into the formula:

mAs(new) = 12 mAs × (1.083 / 1.125) ≈ 11.2 mAs

Therefore, the new mAs should be approximately 11.2 mAs.

User Prakash Bhagat
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.