233k views
1 vote
A 3-inch object to be radiographed at a 36-inch SID lies 4 inches from the image recorder. What will be the image width?

3.3 inches

1 Answer

7 votes

Final answer:

The image width of a 3-inch object with a 36-inch source-to-image distance and lying 4 inches from the image recorder will be approximately 3.375 inches.

Step-by-step explanation:

The image width of an object in radiography can be determined using the magnification formula, which is Image Width = (SID / SOD) × Object Size, where SID is the Source-to-Image Distance, and SOD is the Source-to-Object Distance. For this problem:

  • SID = 36 inches
  • SOD = SID - distance from object to image recorder = 36 inches - 4 inches = 32 inches
  • Object Size = 3 inches

Plugging in the values, we get:

Image Width = (36 / 32) × 3 inches = 1.125 × 3 inches = 3.375 inches.

Therefore, the image width on the film will be approximately 3.375 inches.

User Carlos Granados
by
8.1k points