The average force involved in stopping the football is 625 N.
To calculate the average force involved in stopping the football, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the football has a mass of 0.5 kg and a change in velocity from 10 m/s to 15 m/s in a time interval of 1/50th of a second.
First, we need to calculate the change in velocity:
Δv = final velocity + initial velocity = 15 m/s +10 m/s = 25 m/s
Next, we calculate the acceleration:
a = Δv / t = (25 m/s) / (1/50th s) = 1250 m/s²
Finally, we can calculate the average force:
F = m * a = (0.5 kg) * (1250 m/s²) = 625 N
The average force involved in stopping the football is 625 N. Note that the negative sign indicates that the force is in the opposite direction of the initial velocity.
The probable question may be:
"A player stops a football weighing 0.5 kg which comes flying towards him with a velocity of 10m/s. If the impact lasts for 1/50th sec. and the ball bounces back with a velocity of 15m/s, then the average force involved is"