Question

A cylinder contains 28.5L of oxygen gas at a pressure of 1.8atm and a temperature of 298K. How many moles of gas are in the cylinder?

Answer 1

To calculate the number of moles of oxygen gas in the cylinder, we can use the ideal gas law equation. Substituting the given values, we find that there are 16 moles of oxygen gas in the cylinder.

Step-by-step explanation:

To calculate the number of moles of oxygen gas in the cylinder, we can use the ideal gas law equation:

PV = nRT

Where:

• P is the pressure (in atm)
• V is the volume (in L)
• n is the number of moles
• R is the ideal gas constant (0.0821 L·atm/mol·K)
• T is the temperature (in Kelvin)

First, we need to convert the pressure from atm to mmHg:

1 atm = 760 mmHg

So, the pressure is 1.8 atm x 760 mmHg/atm = 1368 mmHg

Now, we convert the temperature from degrees Celsius to Kelvin:

K = °C + 273.15

So, the temperature is 298 K

Now, we can rearrange the ideal gas law equation to solve for n:

n = (PV) / (RT)

Substituting the values:

n = (1368 mmHg x 28.5 L) / (0.0821 L·atm/mol·K x 298 K)

= 16 moles

Therefore, there are 16 moles of oxygen gas in the cylinder.