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a ring is dropped from helicopter of an altitude of 246 feet how long does it take to ring to reach the ground

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Final answer:

To find the time it takes for the ring to reach the ground, we can use the equation of motion with constant acceleration. Substituting the known values into the equation, we can find the time to be approximately 3.02 seconds.

Step-by-step explanation:

To solve this problem, we can use the equations of motion with constant acceleration.

The knowns in this problem are:

  • Initial velocity (u) = 0 m/s (as the ring is dropped)
  • Final velocity (v) = ? (when the ring reaches the ground)
  • Acceleration (a) = 9.8 m/s² (acceleration due to gravity)
  • Displacement (s) = 246 feet = 75 meters (height from which the ring is dropped)
  • Time (t) = ? (time taken for the ring to reach the ground)

We can use the equation: s = ut + (1/2)at² to solve for time.

Rearranging the equation gives: t² = (2s)/a.

Substituting the values, we get: t² = (2 * 75) / 9.8

. Solving for t, we find t ≈ 3.02 seconds.

Therefore, it takes approximately 3.02 seconds for the ring to reach the ground.

User MefAldemisov
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