Question

If 0.05 second was selected for a particular exposure, what mA would be necessary to produce 15 mAs?

300

Answer 1

To produce an exposure of 15 mAs with a time of 0.05 second, the necessary current would be 300 milliamperes (mA).

Step-by-step explanation:

If a student needs to produce 15 mAs (milliampere-seconds) with an exposure time of 0.05 second, the required current in milliamperes (mA) can be calculated using the formula: mAs = mA × seconds. Therefore, rearranging the formula to solve for mA gives us: mA = mAs / seconds.

Substituting the given values into the formula gives:
mA = 15 mAs / 0.05 s = 300 mA.

Hence, to achieve an exposure of 15 mAs in 0.05 seconds, you would need a current of 300 milliamperes (mA).