Final answer:
To find the projected image width, the magnification formula is adjusted to solve for the image width. With an object width of 6 inches, an SID of 44 inches, and an object distance of 9 inches, the projected image width is approximately 29.3 inches.
Step-by-step explanation:
To determine the projected image width of a part with a given width of 6 inches imaged at an SID (Source to Image Distance) of 44 inches, where the part is 9 inches from the image receptor (IR), you can use the magnification formula:
Magnification (m) = Image Distance (ID) / Object Distance (OD)
However, since you're interested in determining the width rather than the magnification, we rearrange the formula to solve for the projected image width (IW):
IW = Object Width (OW) × ID / OD
Here the object width (OW) is 6 inches, the image distance (ID) is the SID which is 44 inches, and the object distance (OD) is the distance from the object to the IR, which is 9 inches in this case.
Plugging in the numbers:
IW = 6 inches × 44 inches / 9 inches = 29.3 inches (approximately)
The projected image width of the part on the IR will be approximately 29.3 inches.