Question

1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of the electric force? The constant k = 9 x 109 N-m2/C2

Answer 1

Step-by-step explanation:

Charges,
`q_1=8\ \mu C=8* 10^(-6)\ C`

`q_2=-5\ \mu C=-5* 10^(-6)\ C`

The distance between charges, r = 10 cm = 0.1 m

We need to find the magnitude and direction of the electric force. It is given by :

`F=(kq_1q_2)/(r^2)\\\\F=(9* 10^9* 8* 10^(-6)* 5* 10^(-6))/((0.1)^2)\\\\F=36\ N`

So, the required force between charges is 36 N and it is towards positive charge i.e. +8 μC.