Question

The exposure factors of 400 mA, 17 ms, and 82 kV produce a milliampere-seconds value of
6.8

Answer 1

The milliampere-seconds (mAs) value is obtained by multiplying the milliamperes (mA) by the exposure time in seconds (s). In this case, the given exposure factors of 400 mA and 17 ms result in a mAs value of 6.8.

Step-by-step explanation:

The formula for calculating milliampere-seconds (mAs) is given by
`\( \text{mAs} = \frac{ \text{mA} * \text{ms} }{1000} \)`, where mA is the milliamperes and ms is the exposure time in milliseconds. Given the exposure factors of 400 mA and 17 ms, the calculation is as follows:

`\[ \text{mAs} = \frac{400 \, \text{mA} * 17 \, \text{ms}}{1000} = (6800)/(1000) = 6.8 \, \text{mAs} \]`

This indicates that the milliampere-seconds value for this particular X-ray exposure is 6.8 mAs. The mAs value is essential in radiography as it influences the overall exposure of the X-ray image. It represents the product of the tube current (mA) and the exposure time (ms), reflecting the total amount of X-ray radiation delivered during the exposure.

In summary, the given exposure factors of 400 mA and 17 ms yield a milliampere-seconds value of 6.8 mAs. This numerical value is crucial for radiographers in controlling and optimizing the exposure parameters to obtain diagnostic images with the desired quality while minimizing patient radiation exposure.